2m^2+8m-350=0

Solution for 2m^2+8m-350=0 equation:

2m^2+8m-350=0

a = 2; b = 8; c = -350;
Δ = b2-4ac
Δ = 82-4·2·(-350)
Δ = 2864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2864}=\sqrt{16*179}=\sqrt{16}*\sqrt{179}=4\sqrt{179}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{179}}{2*2}=\frac{-8-4\sqrt{179}}{4}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{179}}{2*2}=\frac{-8+4\sqrt{179}}{4}
$